Tuesday, October 4, 2016

Term 1, Turn In #3 Discussion

Turn in #3 is due Monday, Oct. 10, 2016!

This is for discussing assignments from WEEK 5, including homework, turn-in #3, in-class work or lessons, or anything else related to the class from these weeks.  Please be sure to include your name at the end of your post for credit.  When answering a question, DO NOT GIVE SOLUTIONS! Provide hints or explain a method that you used, but do not give the final result.  As always, RESPECT IS A MUST! Anyone abusing this forum will be banned from future use (meaning, no extra credit!!!).

20 comments:

  1. in the turn in for question 4a), how do we find t to plug in the equation?
    estelle

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    1. Mr. Wilson said that if we don't have a T value, you can leave your answers in terms of t.
      Chance

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  2. For 5a on the turn in how do you find the relationship between h (the height of the water in the cone) & y (the height of the water in the cylinder).

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    1. You take the derivative of the equation for the volume of the cone, so you have dV/dt, which is the rate of change of the volume. Assuming we start with the volume being zero, you can use that as the rate of change in feet cubed per minute.
      Chance

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    2. I did that, however the question asks for the equation that represents the volume of the water in the cylindrical tank, not the equation that represents the rate of change of the volume.

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    3. When you think about it, you can find an expression for the volume of the cylindrical tank as being equal to the maximum volume of the conical tank minus the current volume of the conical tank (so for the max volume you would substitute in the given height of the tank and for current volume you would leave h alone).
      -Evan Gilman

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    4. This comment has been removed by the author.

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    5. ah sorry I deleted it. First of all, in 5a, I forgot how to take into account the fact that r is changing as well as the height, how do I do that? Also, do I have to use the expression h-12 in my answer in part a? Its asking for cylindrical, not conical, so Im not sure

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  3. This comment has been removed by the author.

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    1. take the derivative of the equation that represents the volume of the water in the cylindrical tank, and use the answer to 5b times -1 as your value of dV/dt to solve for dY/dt.

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    2. in 5c how do I isolate the depth of the water in the cylindrical tank?
      Andrew Saad

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    3. sorry i deleted the question that was an accident :)

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    4. Remember the volume of a cylinder is V=πr^2h

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    5. The equation for the volume of water in the cylindrical tank was found in part a, so if you recognize that the equation for that volume is: V = base*depth (depth = height), then you will realize that you can divide the expression you got in part a by the given base area to isolate depth (y).
      -Evan Gilman

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  4. For 4a, should t just be left as a variable or does it need to be solved for?

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    1. t should just be left as a variable
      Andrew Saad

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  5. For 5a do we assume that the cone started out full?

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  6. for 4b, don't you have to know the radius of the sphere at it's max volume to find it's max volume? Do I have to know the max volume to find t? How do I do that? -Charlotte Beggs (I have a feeling this is an obvious answer so I'm sorry)

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  7. You don't need either of them, remember that when the volume is at its max it cant change anymore, must find when volume is not changing. -Trent Pitser

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